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ffmpeg / libavutil / mem.c @ b76e3424

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/*
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 * default memory allocator for libavutil
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 * Copyright (c) 2002 Fabrice Bellard.
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 *
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 * This file is part of FFmpeg.
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 *
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 * FFmpeg is free software; you can redistribute it and/or
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 * modify it under the terms of the GNU Lesser General Public
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 * License as published by the Free Software Foundation; either
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 * version 2.1 of the License, or (at your option) any later version.
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 *
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 * FFmpeg is distributed in the hope that it will be useful,
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 * but WITHOUT ANY WARRANTY; without even the implied warranty of
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 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
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 * Lesser General Public License for more details.
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 *
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 * You should have received a copy of the GNU Lesser General Public
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 * License along with FFmpeg; if not, write to the Free Software
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 * Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
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 */
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/**
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 * @file mem.c
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 * default memory allocator for libavutil.
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 */
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#include "common.h"
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/* here we can use OS dependent allocation functions */
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#undef malloc
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#undef free
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#undef realloc
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#ifdef HAVE_MALLOC_H
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#include <malloc.h>
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#endif
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/* you can redefine av_malloc and av_free in your project to use your
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   memory allocator. You do not need to suppress this file because the
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   linker will do it automatically */
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void *av_malloc(unsigned int size)
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{
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    void *ptr;
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#ifdef CONFIG_MEMALIGN_HACK
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    long diff;
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#endif
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    /* let's disallow possible ambiguous cases */
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    if(size > (INT_MAX-16) )
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        return NULL;
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#ifdef CONFIG_MEMALIGN_HACK
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    ptr = malloc(size+16);
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    if(!ptr)
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        return ptr;
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    diff= ((-(long)ptr - 1)&15) + 1;
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    ptr = (char*)ptr + diff;
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    ((char*)ptr)[-1]= diff;
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#elif defined (HAVE_MEMALIGN)
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    ptr = memalign(16,size);
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    /* Why 64?
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       Indeed, we should align it:
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         on 4 for 386
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         on 16 for 486
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         on 32 for 586, PPro - k6-III
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         on 64 for K7 (maybe for P3 too).
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       Because L1 and L2 caches are aligned on those values.
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       But I don't want to code such logic here!
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     */
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     /* Why 16?
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        Because some CPUs need alignment, for example SSE2 on P4, & most RISC CPUs
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        it will just trigger an exception and the unaligned load will be done in the
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        exception handler or it will just segfault (SSE2 on P4)
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        Why not larger? Because I did not see a difference in benchmarks ...
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     */
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     /* benchmarks with p3
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        memalign(64)+1          3071,3051,3032
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        memalign(64)+2          3051,3032,3041
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        memalign(64)+4          2911,2896,2915
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        memalign(64)+8          2545,2554,2550
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        memalign(64)+16         2543,2572,2563
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        memalign(64)+32         2546,2545,2571
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        memalign(64)+64         2570,2533,2558
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        btw, malloc seems to do 8 byte alignment by default here
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     */
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#else
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    ptr = malloc(size);
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#endif
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    return ptr;
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}
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void *av_realloc(void *ptr, unsigned int size)
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{
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#ifdef CONFIG_MEMALIGN_HACK
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    int diff;
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#endif
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    /* let's disallow possible ambiguous cases */
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    if(size > (INT_MAX-16) )
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        return NULL;
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#ifdef CONFIG_MEMALIGN_HACK
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    //FIXME this isn't aligned correctly, though it probably isn't needed
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    if(!ptr) return av_malloc(size);
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    diff= ((char*)ptr)[-1];
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    return (char*)realloc((char*)ptr - diff, size + diff) + diff;
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#else
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    return realloc(ptr, size);
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#endif
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}
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void av_free(void *ptr)
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{
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    /* XXX: this test should not be needed on most libcs */
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    if (ptr)
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#ifdef CONFIG_MEMALIGN_HACK
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        free((char*)ptr - ((char*)ptr)[-1]);
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#else
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        free(ptr);
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#endif
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}
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void av_freep(void *arg)
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{
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    void **ptr= (void**)arg;
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    av_free(*ptr);
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    *ptr = NULL;
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}
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void *av_mallocz(unsigned int size)
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{
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    void *ptr = av_malloc(size);
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    if (ptr)
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        memset(ptr, 0, size);
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    return ptr;
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}
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char *av_strdup(const char *s)
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{
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    char *ptr= NULL;
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    if(s){
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        int len = strlen(s) + 1;
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        ptr = av_malloc(len);
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        if (ptr)
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            memcpy(ptr, s, len);
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    }
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    return ptr;
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}
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